# Projectile Motion-Height of Projectile, Time of Flight, and Range of Projectile

Projectile motion is a form of motion experienced by an object or particle (projectile) that is projected near the surface of the earth and moves along a curved path under the action of gravity.

*Projectile motion is a two-dimensional motion under constant acceleration due to gravity.*

## What is a Projectile?

** A projectile is any object projected in space with a certain initial velocity in an arbitrary direction and then allowed to move under the influence of gravity**.

## What is Trajectory?

*The path followed by the projectile is called the trajectory*

**Examples**

- A football kicked by a player
- A ball was thrown by a cricketer
- Rocket Propulsion.

All bodies projected at some angles with the horizontal are examples of projectiles.

Consider the motion of a ball, when it is thrown horizontally from a certain height observed that the ball travels forward direction as well as falls down until it strikes something.

The motion of a projectile can be studied easily by resolving it into horizontal and vertical components which are independent of each other

## Horizontal Projectile Motion

Suppose that the ball leaves the hand of the thrower at point A its velocity at that instant is completely horizontal

Let this velocity be V_{x}

- According to Newton’s law of motion, there will be no acceleration in the horizontal direction, unless a horizontally directed force acts on the ball.
- A body remains at rest or continues to move with constant velocity provided no external force acts on the body.

Ignoring the air friction, the only force acting on the ball during flight is the force of gravity. There is no horizontal force acting on it.

So its horizontal velocity will remain unchanged and will be Vx until the ball hits something. The horizontal motion of the ball is simple.

The ball moves with a constant horizontal velocity component.

## The horizontal distance of Projectile:

Horizontal distance x is given by

**X=V _{x} xt**

## Vertical Projectile Motion:

The ball will accelerate downward under the force of gravity and hence a=g. This vertical motion is the same as for a freely falling body. Since the initial vertical is zero.

## The vertical distance of Projectile:

The vertical distance of the object can be calculated as,

S=V_{i}t+(1/2)at^{2}

y=(0)t+(1/2)gt^{2}

**y=(1/2)gt ^{2}**

When the projectile is making some angle with the horizontal axis. Suppose that a projectile is fired at an angle **Î¸** with the horizontal velocity V_{i}.

Let components of velocity V_{i} along the horizontal and vertical direction be V_{i} cosÎ¸ and V_{i} sinÎ¸ respectively.

## Horizontal Velocity of Projectile Motion

The horizontal acceleration is **a _{x} = 0** because air resistance has been neglected and no other force is acting in this direction. Hence the horizontal component V

_{ix}remains constant and at any time t

**V _{fx} = V_{i} = V_{i} cosÎ¸**

## Vertical Velocity of Projectile Motion

In vertical motion, vertical acceleration** a _{y}= g**. The initial vertical component of the velocity is V

_{i}sin Î¸ in the upward direction

V_{iy} = V_{i} SinÎ¸

The vertical component V_{fy} of the velocity at any instant t is given by

Vf=Vi-at

Vfy= V_{i} SinÎ¸ -gt

## Instantaneous Velocity of the Projectile

The magnitude of velocity at any instant t is

## Equation of Direction of projectile motion

**TanÎ¸=V _{fy}/V_{fx}**

Î¸ is the angel with which body is projectile

## Height of Projectile:

*“The greatest vertical distance reached as measured from the horizontal projection plane”.*

In order to determine the maximum height of the projectile, we use 3^{rd} eq. of motion

2as = v_{f}Â² – v_{i}Â²

The body moves upward, so a = -g

initial vertical velocity= V_{iy} = V_{i}SinÎ¸

the body comes to rest after reaching the highest point, so V_{fy}= 0

## Time of Flight

*“The time is taken by the body to cover the distance from the place of its projection to the place where it hits the ground is called the time of flight”.*

Let’s consider if the body is projected with velocity v making an angle Î¸ with the horizontal, then its vertical component will be V_{i} Sin Î¸.

**s = h = 0** because the body goes up and comes back to the same level, thus covering no vertical distance

Where t is the time of flight of the projectile when it is projected from the ground

## Â Range of the Projectile

*The maximum distance that a projectile covers in the horizontal direction is called the range of the projectile.*

The range R of the projectile is equal to the product of the horizontal component of the velocity of projection with the total time taken by the body to hit the ground after leaving the point of projection.

## Dependence of range:

Thus the range of the projectile depends upon the velocity of projection and the angle of projection.

## What is the maximum range of projectile?

For range R to be maximum, the factor sin2Î¸ should have a maximum value which is 1

## Frequently Asked Question

### What does Projectile motion mean?

Projectile motion is a two-dimensional motion under constant acceleration due to gravity.

### What are the main factors that affect the projectile motion?

There are three main factors on which projectile motion depends.

**The projection angle****The magnitude of projection velocity****Height of the projection**

### When does the projectile have maximum range?

The projectile has a maximum range at an angle of 45.

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