10th Chapter Solved Exercise MCQs of FSC First Year Chemistry
written by Almas AnwarThe 10th chapter Solved Exercise MCQs of FSC 1st-year Chemistry offers a comprehensive collection of multiple-choice questions with answers. Each question is accompanied by a short explanation to clarify the correct choice. These solutions aim to assist students in exam preparation by simplifying complex concepts and building a strong foundation for success.
10th chapter solved MCQs with explanation
1. The cathodic reaction in the electrolysis of dil. H₂SO₄ with Pt electrodes is:
(a) Reduction
(b) Oxidation
(c) Both oxidation and reduction
(d) Neither oxidation nor reduction
Explanation: The correct answer is (a). Because In the electrolysis of dilute sulfuric acid (H₂SO₄) with platinum (Pt) electrodes, the cathodic reaction involves the reduction of hydrogen ions (H⁺) from the solution to form hydrogen gas (H₂).
The overall cathodic reaction is: 2H+ + 2e− → H2
At the cathode, reduction is taking place because hydrogen ions are gaining electrons to become hydrogen gas.
2. Which of the following statements is not correct about galvanic cell?
(a) Anode is negatively charged
(b) Reduction occurs at anode
(c) Cathode is positively charged
(d) Reduction occurs at cathode
Explanation: The correct answer is (b). Because in a galvanic cell:
- The anode is negatively charged, and oxidation occurs at the anode. This is where electrons are released.
- The cathode is positively charged, and reduction occurs at the cathode. This is where electrons are gained.
3. Stronger the oxidizing agent, greater is the:
(a) oxidation potential
(b) reduction potential
(c) redox potential
(d) E.M.F of cell
Explanation: The correct answer is (b). Because:
- A stronger oxidizing agent has a higher reduction potential because it easily gains electrons.
- Reduction potential measures how likely a substance is to be reduced (gain electrons).
Thus, a stronger oxidizing agent will have a higher reduction potential.
4. If the salt bridge is not used between two half cells, then the voltage:
(a) Decrease rapidly
(b) Decrease slowly
(c) Does not change
(d) Drops to zero
Explanation: The correct answer is (d). Because a salt bridge helps balance the charges in each part of the battery. Without it, the charges build up and stop the flow of electricity. Therefore, if you don’t use a salt bridge, the voltage will drop to zero because the battery stops working.
5. If a strip of Cu metal is placed in a solution of FeSO₄:
(a) Cu will be deposited
(b) Fe is precipitated out
(c) Cu and Fe both dissolve
(d) No reaction takes place
Explanation: The correct answer is (d). Because Cu lies below Fe in the electrochemical or reactivity series. Hence, it cannot displace Fe from its solution, and thus, no reaction will take place.
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