Roots of a Quadratic Equation | Discriminate of Quadratic Equation
We will discuss here the different cases of discriminant to understand the nature of the roots of a quadratic equation.
We know that the roots of the quadratic equation ax2+bx+c=0 where a≠0 are given by the quadratic formula as:
x=-b±√(b^2-4ac/2a
We see that there are two possible values for x, as discriminated by the parts of the formula
±√ (b^2-4ac).
The nature of the roots of an equation depends on the value of the expression b2-4ac, which is called its discrimination.
Discriminate of Quadratic Equation
The expression (b2-4ac) is called the discriminant of the quadratic equation.
Generally denoted by discriminant of the quadratic equation, D or ∆
Therefore,
Discriminant =∆= b2-4ac
We shall discuss the following cases about the nature of the roots of the quadratic equation ax2+bx+c=0
When a,b, and c are real numbers,a≠0
Case:1.When discriminant is equal to zero(b2-4ac=0)
If the discriminant is equal to zero (b2-4ac=0), then the roots of a quadratic equation are real and repeated equally.
For example:- find the nature of the roots of the quadratic equation .9x2-12x+4=0 by solving them
Solution: 9x2-12x+4=0 comparing with ax2+bx+c=0
We have, a=9, b=-12, c=4
Discriminant =∆=b2-4ac
Discriminant =∆= (-12)2-4(9)(4)
Discriminant =∆= 144-144
Discriminant =∆=0
Clearly, the discriminant of the given quadratic equation is zero.
Therefore, the roots of the given quadratic equation are real and equal.
Solve the equation:
9x2-12x+4=0
9x2-6x-6x+4=0 ∴ by using the factorization method
3x (3x-2)-2(3x-2) =0
(3x-2)(3x-2)=0
3x-2=0 or 3x-2=0
3x=2 3x=2
X=2/3 x=2/3
The given equation has two solutions: 2/3 and 2/3
Solution set ={2/3,2/3}
The solution of an equation is also called its roots.
Clearly, the roots of a given quadratic equation are real and equal.
Case:2.When discriminant is less than zero or negative (b2-4ac<0)
If the discriminant is negative (b2-4ac<0) then√(b^2-4ac will be imaginary so the roots of a quadratic equation are complex/imaginary and distinct/unequal.
For example: Discuss the nature of the roots of a quadratic equation.x2+2x+3=0
Solution:
x2+2x+3=0 comparing with ax2+bx+c=0,we have
a=1 ,b=2,c=3
Discriminant =∆=b2-4ac
Discriminant =∆=(2)2-4(1)(3)
Discriminant =∆=4-12
Discriminant =∆=-8
Clearly, the discriminant of the given quadratic equation (2nd-degree polynomial) is negative.
Therefore, the roots of the given quadratic equation are imaginary and distinct/unequal.
Solve the equation:
x2+2x+3=0
Comparing the standard form of quadratic equation
a=1,b=2,c=3
By using the quadratic formula
x=-b±√(b^2-4ac/2a
Put the value a, b and c
x=-(2)±√(2^2-4(1)(3)/2(1)
x=-2±√(4-12/2
x=-2±√(-8/2
x=-2±√(4X2 i/2
x=-2±2√(2 i/2
x=2(-1±√(2 i)/2
x=-1±√2 i
Clearly, the roots of the given equation are imaginary and unequal
Case:3. When discriminant is greater than zero or positive (b2-4ac>0)
If the discriminant is positive (b2-4ac>0) then √(b^2-4ac will be real .then the roots of a quadratic equation are real and distinct/unequal.
For example:- Discuss the nature of the roots of quadratic equation 2x2+5x-1=0
Solution:
2x2+5x-1=0 comparing with ax2+bx+c=0 we have
a=2,b=5,c=-1
Discriminant =∆=b2-4ac
Discriminant =∆= (5)2-4(2)(-1)
Discriminant =∆=25+8
Discriminant =∆=33
Clearly, the discriminant of a given quadratic equation is positive.
Therefore, the roots of the given quadratic equation are real and distinct /unequal.
Case:4. When discriminant is greater than zero and perfect square (b2-4ac>0 )
If the discriminant is greater than zero (b2-4ac>0) or positive and perfect square then the roots of a quadratic equation are real, rational, and unequal.
For example: Discuss the nature of the roots of the quadratic equation (p+q) x2-px-q=0
Solution:
(p+q) x2-px-q=0 comparing with ax2+bx+c=0 we have
a=(p+q) ,b=-p ,c=-q
Discriminant =∆=b2-4ac
Discriminant =∆=(-p)2-4(p+q)(-q)
Discriminant =∆=p2+4pq+4q2
Discriminant =∆=p2+2(p)(2q)+(2q)2
Discriminant =∆= (p+q) 2
Which is a perfect square
Hence the roots of a given quadratic equation are
Real, rational, and unequal
For example: x2+4x+3=0
Solution:
x2+4x+3=0 comparing with ax2+bx+c=0 we have
a=1 ,b=4 ,c=3
Discriminant =∆=b2-4ac
Discriminant =∆=(4)2-4(1)(3)
Discriminant =∆=16-12
Discriminant =∆=4
Discriminant =∆=(2)2 >0
Which is a perfect square
Solve the equation:
x2+4x+3=0
By using the factorization method
X2+3x+x+3=0
X(x+3)+1(x+3)=0
(x+3)(x+1)=0
X+3=0 or x+1=0
X=-3 x=-1
Solution set={-3,-1}
Clearly, the discriminant is given an equation greater than zero and a perfect square.
Clearly, the roots of the given equation are real, rational, and unequal.
Case 5:- When the discriminant is greater than zero and not a perfect square (b2-4ac>0 )
If the discriminant is positive but not a perfect square then the roots of the quadratic equation are real, irrational,unequal
For example: Discuss the nature of the roots of quadratic equations.4x2+6x+1=0
Solution:
4x2+6x+1=0 comparing with ax2+bx+c=0 we have
a=4 ,b=6 ,c=1
Discriminant =∆=b2-4ac
Discriminant =∆= (6)2– 4(4)(1)
Discriminant =∆=36-16
Discriminant =∆= 20>0 but not a perfect square
Clearly, if the discriminant of the given quadratic equation is greater than zero but not perfect square the roots of the quadratic equation are real, unequal, and irrational.
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